Chapter 3: Motion in a Straight Line

Equations of Motion:
• v = u + at
• s = ut + ⅔at²
• v² = u² + 2as

Q1. A car accelerates from 20 m/s to 60 m/s in 5 s. Find the acceleration and distance covered.

Solution

a = (60-20)/5 = 8 m/s²
s = 20(5) + ⅔(8)(25) = 100 + 100 = 200 m

Q2. A body is thrown vertically upward with velocity 40 m/s. Find the maximum height. (g = 10 m/s²)

Solution

At max height, v = 0
0 = 40² - 2(10)h
h = 1600/20 = 80 m