Chapter 14: Oscillations
• x = A sin(ωt + φ)
• T = 2π√(l/g) (simple pendulum)
• ω = 2π/T
• E = ⅔mω²A²
Q1. Find the time period of a simple pendulum of length 1 m on Earth.
SolutionT = 2π√(l/g) = 2π√(1/9.8) ≈ 2 s
Q2. A particle executes SHM with amplitude 5 cm and frequency 10 Hz. Find maximum velocity.
Solutionω = 2π(10) = 20π rad/s
vmax = Aω = 0.05 × 20π = π ≈ 3.14 m/s